referenced before assignment python

Fix "local variable referenced before assignment" in Python

Introduction

If you're a Python developer, you've probably come across a variety of errors, like the "local variable referenced before assignment" error. This error can be a bit puzzling, especially for beginners and when it involves local/global variables.

Today, we'll explain this error, understand why it occurs, and see how you can fix it.

The "local variable referenced before assignment" Error

The "local variable referenced before assignment" error in Python is a common error that occurs when a local variable is referenced before it has been assigned a value. This error is a type of UnboundLocalError , which is raised when a local variable is referenced before it has been assigned in the local scope.

Here's a simple example:

Running this code will throw the "local variable 'x' referenced before assignment" error. This is because the variable x is referenced in the print(x) statement before it is assigned a value in the local scope of the foo function.

Even more confusing is when it involves global variables. For example, the following code also produces the error:

But wait, why does this also produce the error? Isn't x assigned before it's used in the say_hello function? The problem here is that x is a global variable when assigned "Hello ". However, in the say_hello function, it's a different local variable, which has not yet been assigned.

We'll see later in this Byte how you can fix these cases as well.

Fixing the Error: Initialization

One way to fix this error is to initialize the variable before using it. This ensures that the variable exists in the local scope before it is referenced.

Let's correct the error from our first example:

In this revised code, we initialize x with a value of 1 before printing it. Now, when you run the function, it will print 1 without any errors.

Fixing the Error: Global Keyword

Another way to fix this error, depending on your specific scenario, is by using the global keyword. This is especially useful when you want to use a global variable inside a function.

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Here's how:

In this snippet, we declare x as a global variable inside the function foo . This tells Python to look for x in the global scope, not the local one . Now, when you run the function, it will increment the global x by 1 and print 1 .

Similar Error: NameError

An error that's similar to the "local variable referenced before assignment" error is the NameError . This is raised when you try to use a variable or a function name that has not been defined yet.

Running this code will result in a NameError :

In this case, we're trying to print the value of y , but y has not been defined anywhere in the code. Hence, Python raises a NameError . This is similar in that we are trying to use an uninitialized/undefined variable, but the main difference is that we didn't try to initialize y anywhere else in our code.

Variable Scope in Python

Understanding the concept of variable scope can help avoid many common errors in Python, including the main error of interest in this Byte. But what exactly is variable scope?

In Python, variables have two types of scope - global and local. A variable declared inside a function is known as a local variable, while a variable declared outside a function is a global variable.

Consider this example:

In this code, x is a global variable, and y is a local variable. x can be accessed anywhere in the code, but y can only be accessed within my_function . Confusion surrounding this is one of the most common causes for the "variable referenced before assignment" error.

In this Byte, we've taken a look at the "local variable referenced before assignment" error and another similar error, NameError . We also delved into the concept of variable scope in Python, which is an important concept to understand to avoid these errors. If you're seeing one of these errors, check the scope of your variables and make sure they're being assigned before they're being used.

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How to Fix Local Variable Referenced Before Assignment Error in Python

Fixing local variable referenced before assignment error.

In Python , when you try to reference a variable that hasn't yet been given a value (assigned), it will throw an error.

That error will look like this:

In this post, we'll see examples of what causes this and how to fix it.

Let's begin by looking at an example of this error:

If you run this code, you'll get

The issue is that in this line:

We are defining a local variable called value and then trying to use it before it has been assigned a value, instead of using the variable that we defined in the first line.

If we want to refer the variable that was defined in the first line, we can make use of the global keyword.

The global keyword is used to refer to a variable that is defined outside of a function.

Let's look at how using global can fix our issue here:

Global variables have global scope, so you can referenced them anywhere in your code, thus avoiding the error.

If you run this code, you'll get this output:

In this post, we learned at how to avoid the local variable referenced before assignment error in Python.

The error stems from trying to refer to a variable without an assigned value, so either make use of a global variable using the global keyword, or assign the variable a value before using it.

Thanks for reading!

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Python local variable referenced before assignment Solution

When you start introducing functions into your code, you’re bound to encounter an UnboundLocalError at some point. This error is raised when you try to use a variable before it has been assigned in the local context .

In this guide, we talk about what this error means and why it is raised. We walk through an example of this error in action to help you understand how you can solve it.

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What is unboundlocalerror: local variable referenced before assignment.

Trying to assign a value to a variable that does not have local scope can result in this error:

Python has a simple rule to determine the scope of a variable. If a variable is assigned in a function , that variable is local. This is because it is assumed that when you define a variable inside a function you only need to access it inside that function.

There are two variable scopes in Python: local and global. Global variables are accessible throughout an entire program; local variables are only accessible within the function in which they are originally defined.

Let’s take a look at how to solve this error.

An Example Scenario

We’re going to write a program that calculates the grade a student has earned in class.

We start by declaring two variables:

These variables store the numerical and letter grades a student has earned, respectively. By default, the value of “letter” is “F”. Next, we write a function that calculates a student’s letter grade based on their numerical grade using an “if” statement :

Finally, we call our function:

This line of code prints out the value returned by the calculate_grade() function to the console. We pass through one parameter into our function: numerical. This is the numerical value of the grade a student has earned.

Let’s run our code and see what happens:

An error has been raised.

The Solution

Our code returns an error because we reference “letter” before we assign it.

We have set the value of “numerical” to 42. Our if statement does not set a value for any grade over 50. This means that when we call our calculate_grade() function, our return statement does not know the value to which we are referring.

We do define “letter” at the start of our program. However, we define it in the global context. Python treats “return letter” as trying to return a local variable called “letter”, not a global variable.

We solve this problem in two ways. First, we can add an else statement to our code. This ensures we declare “letter” before we try to return it:

Let’s try to run our code again:

Our code successfully prints out the student’s grade.

If you are using an “if” statement where you declare a variable, you should make sure there is an “else” statement in place. This will make sure that even if none of your if statements evaluate to True, you can still set a value for the variable with which you are going to work.

Alternatively, we could use the “global” keyword to make our global keyword available in the local context in our calculate_grade() function. However, this approach is likely to lead to more confusing code and other issues. In general, variables should not be declared using “global” unless absolutely necessary . Your first, and main, port of call should always be to make sure that a variable is correctly defined.

In the example above, for instance, we did not check that the variable “letter” was defined in all use cases.

That’s it! We have fixed the local variable error in our code.

The UnboundLocalError: local variable referenced before assignment error is raised when you try to assign a value to a local variable before it has been declared. You can solve this error by ensuring that a local variable is declared before you assign it a value.

Now you’re ready to solve UnboundLocalError Python errors like a professional developer !

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Local variable referenced before assignment in Python

Last updated: Apr 8, 2024 Reading time · 4 min

# Local variable referenced before assignment in Python

The Python "UnboundLocalError: Local variable referenced before assignment" occurs when we reference a local variable before assigning a value to it in a function.

To solve the error, mark the variable as global in the function definition, e.g. global my_var .

unboundlocalerror local variable name referenced before assignment

Here is an example of how the error occurs.

We assign a value to the name variable in the function.

# Mark the variable as global to solve the error

To solve the error, mark the variable as global in your function definition.

If a variable is assigned a value in a function's body, it is a local variable unless explicitly declared as global .

# Local variables shadow global ones with the same name

You could reference the global name variable from inside the function but if you assign a value to the variable in the function's body, the local variable shadows the global one.

Accessing the name variable in the function is perfectly fine.

On the other hand, variables declared in a function cannot be accessed from the global scope.

variables declared in function cannot be accessed in global scope

The name variable is declared in the function, so trying to access it from outside causes an error.

Make sure you don't try to access the variable before using the global keyword, otherwise, you'd get the SyntaxError: name 'X' is used prior to global declaration error.

# Returning a value from the function instead

An alternative solution to using the global keyword is to return a value from the function and use the value to reassign the global variable.

We simply return the value that we eventually use to assign to the name global variable.

# Passing the global variable as an argument to the function

You should also consider passing the global variable as an argument to the function.

pass global variable as argument to function

We passed the name global variable as an argument to the function.

If we assign a value to a variable in a function, the variable is assumed to be local unless explicitly declared as global .

# Assigning a value to a local variable from an outer scope

If you have a nested function and are trying to assign a value to the local variables from the outer function, use the nonlocal keyword.

assign value to local variable from outer scope

The nonlocal keyword allows us to work with the local variables of enclosing functions.

Had we not used the nonlocal statement, the call to the print() function would have returned an empty string.

Printing the message variable on the last line of the function shows an empty string because the inner() function has its own scope.

Changing the value of the variable in the inner scope is not possible unless we use the nonlocal keyword.

Instead, the message variable in the inner function simply shadows the variable with the same name from the outer scope.

# Discussion

As shown in this section of the documentation, when you assign a value to a variable inside a function, the variable:

Becomes local to the scope.
Shadows any variables from the outer scope that have the same name.

The last line in the example function assigns a value to the name variable, marking it as a local variable and shadowing the name variable from the outer scope.

At the time the print(name) line runs, the name variable is not yet initialized, which causes the error.

The most intuitive way to solve the error is to use the global keyword.

The global keyword is used to indicate to Python that we are actually modifying the value of the name variable from the outer scope.

If a variable is only referenced inside a function, it is implicitly global.
If a variable is assigned a value inside a function's body, it is assumed to be local, unless explicitly marked as global .

If you want to read more about why this error occurs, check out [this section] ( this section ) of the docs.

# Additional Resources

You can learn more about the related topics by checking out the following tutorials:

SyntaxError: name 'X' is used prior to global declaration

Borislav Hadzhiev

Web Developer

How to fix UnboundLocalError: local variable 'x' referenced before assignment in Python

You could also see this error when you forget to pass the variable as an argument to your function.

How to reproduce this error

How to fix this error.

I hope this tutorial is useful. See you in other tutorials.

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Local variable referenced before assignment in Python

The “local variable referenced before assignment” error occurs when you try to use a local variable before it has been assigned a value. This is a general programming concept describing the situation typically arises in situations where you declare a variable within a function but then try to access or modify it before actually assigning a value to it.

In Python, the compiler might throw the exact error: “UnboundLocalError: cannot access local variable ‘x’ where it is not associated with a value”

Here’s an example to illustrate this error:

In this example, you would encounter the above error because you’re trying to print the value of x before it has been assigned a value. To fix this, you should assign a value to x before attempting to access it:

In the corrected version, the local variable x is assigned a value before it’s used, preventing the error.

Keep in mind that Python treats variables inside functions as local unless explicitly stated otherwise using the global keyword (for global variables) or the nonlocal keyword (for variables in nested functions).

If you encounter this error and you’re sure that the variable should have been assigned a value before its use, double-check your code for any logical errors or typos that might be causing the variable to not be assigned properly.

Using the global keyword

If you have a global variable named letter and you try to modify it inside a function without declaring it as global, you will get error.

This is because Python assumes that any variable that is assigned a value inside a function is a local variable, unless you explicitly tell it otherwise.

To fix this error, you can use the global keyword to indicate that you want to use the global variable:

Using nonlocal keyword

The nonlocal keyword is used to work with variables inside nested functions, where the variable should not belong to the inner function. It allows you to modify the value of a non-local variable in the outer scope.

For example, if you have a function outer that defines a variable x , and another function inner inside outer that tries to change the value of x , you need to use the nonlocal keyword to tell Python that you are referring to the x defined in outer , not a new local variable in inner .

Here is an example of how to use the nonlocal keyword:

If you don’t use the nonlocal keyword, Python will create a new local variable x in inner , and the value of x in outer will not be changed:

Adventures in Machine Learning

4 ways to fix local variable referenced before assignment error in python, resolving the local variable referenced before assignment error in python.

Python is one of the world’s most popular programming languages due to its simplicity, readability, and versatility. Despite its many advantages, when coding in Python, one may encounter various errors, with the most common being the “local variable referenced before assignment” error.

Even the most experienced Python developers have encountered this error at some point in their programming career. In this article, we will look at four effective strategies for resolving the local variable referenced before assignment error in Python.

Strategy 1: Assigning a Value before Referencing

The first strategy is to assign a value to a variable before referencing it. The error occurs when the variable is referenced before it is assigned a value.

This problem can be avoided by initializing the variable before referencing it. For example, let us consider the snippet below:

In the snippet above, the variables x and y are not assigned values before they are referenced in the print statement. Therefore, we will get a local variable “referenced before assignment” error.

To resolve this error, we must initialize the variables before referencing them. We can avoid this error by assigning a value to x and y before they are referenced, as shown below:

Strategy 2: Using the Global Keyword

In Python, variables declared inside a function are considered local variables. Thus, they are separate from other variables declared outside of the function.

If we want to use a variable outside of the function, we must use the global keyword. Using the global keyword tells Python that you want to use the variable that was defined globally, not locally.

For example:

In the code snippet above, the global keyword tells Python to use the variable x defined outside of the function rather than a local variable named x . Thus, Python will output 30.

Strategy 3: Adding Input Parameters for Functions

Another way to avoid the local variable referenced before assignment error is by adding input parameters to functions.

In the code snippet above, x and y are variables that are passed into the add_numbers function as arguments.

This approach allows us to avoid the local variable referenced before assignment error because the variables are being passed into the function as input parameters.

Strategy 4: Initializing Variables before Loops or Conditionals

Finally, it’s also a good practice to initialize the variables before loops or conditionals.

If you are defining a variable within a loop, you must initialize it before the loop starts. This way, the variable already exists, and we can update the value inside the loop.

In the code snippet above, the variable sum has been initialized with the value of 0 before the loop runs. Thus, we can update and use the variable inside the loop.

In conclusion, the “local variable referenced before assignment” error is a common issue in Python. However, with the strategies discussed in this article, you can avoid the error and write clean Python code.

Remember to initialize your variables, use the global keyword, add input parameters in functions, and initialize variables before loops or conditionals. By following these techniques, your Python code will be error-free and much easier to manage.

In essence, this article has provided four key strategies for resolving the “local variable referenced before assignment” error that is common in Python. These strategies include initializing variables before referencing, using the global keyword, adding input parameters to functions, and initializing variables before loops or conditionals.

These techniques help to ensure clean code that is free from errors. By implementing these strategies, developers can improve their code quality and avoid time-wasting errors that can occur in their work.

UnboundLocalError Local variable Referenced Before Assignment in Python

Handling errors is an integral part of writing robust and reliable Python code. One common stumbling block that developers often encounter is the “UnboundLocalError” raised within a try-except block. This error can be perplexing for those unfamiliar with its nuances but fear not – in this article, we will delve into the intricacies of the UnboundLocalError and provide a comprehensive guide on how to effectively use try-except statements to resolve it.

What is UnboundLocalError Local variable Referenced Before Assignment in Python?

The UnboundLocalError occurs when a local variable is referenced before it has been assigned a value within a function or method. This error typically surfaces when utilizing try-except blocks to handle exceptions, creating a puzzle for developers trying to comprehend its origins and find a solution.

Why does UnboundLocalError: Local variable Referenced Before Assignment Occur?

below, are the reasons of occurring “Unboundlocalerror: Try Except Statements” in Python :

Variable Assignment Inside Try Block

Reassigning a global variable inside except block.

Accessing a Variable Defined Inside an If Block

In the below code, example_function attempts to execute some_operation within a try-except block. If an exception occurs, it prints an error message. However, if no exception occurs, it prints the value of the variable result outside the try block, leading to an UnboundLocalError since result might not be defined if an exception was caught.

In below code , modify_global function attempts to increment the global variable global_var within a try block, but it raises an UnboundLocalError. This error occurs because the function treats global_var as a local variable due to the assignment operation within the try block.

Solution for UnboundLocalError Local variable Referenced Before Assignment

Below, are the approaches to solve “Unboundlocalerror: Try Except Statements”.

Initialize Variables Outside the Try Block

Avoid reassignment of global variables.

In modification to the example_function is correct. Initializing the variable result before the try block ensures that it exists even if an exception occurs within the try block. This helps prevent UnboundLocalError when trying to access result in the print statement outside the try block.

Below, code calculates a new value ( local_var ) based on the global variable and then prints both the local and global variables separately. It demonstrates that the global variable is accessed directly without being reassigned within the function.

In conclusion , To fix “UnboundLocalError” related to try-except statements, ensure that variables used within the try block are initialized before the try block starts. This can be achieved by declaring the variables with default values or assigning them None outside the try block. Additionally, when modifying global variables within a try block, use the `global` keyword to explicitly declare them.

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Python UnboundLocalError: local variable referenced before assignment

by Suf | Programming , Python , Tips

If you try to reference a local variable before assigning a value to it within the body of a function, you will encounter the UnboundLocalError: local variable referenced before assignment.

The preferable way to solve this error is to pass parameters to your function, for example:

Alternatively, you can declare the variable as global to access it while inside a function. For example,

This tutorial will go through the error in detail and how to solve it with code examples .

What is scope in python, unboundlocalerror: local variable referenced before assignment, solution #1: passing parameters to the function, solution #2: use global keyword, solution #1: include else statement, solution #2: use global keyword.

Scope refers to a variable being only available inside the region where it was created. A variable created inside a function belongs to the local scope of that function, and we can only use that variable inside that function.

A variable created in the main body of the Python code is a global variable and belongs to the global scope. Global variables are available within any scope, global and local.

UnboundLocalError occurs when we try to modify a variable defined as local before creating it. If we only need to read a variable within a function, we can do so without using the global keyword. Consider the following example that demonstrates a variable var created with global scope and accessed from test_func :

If we try to assign a value to var within test_func , the Python interpreter will raise the UnboundLocalError:

This error occurs because when we make an assignment to a variable in a scope, that variable becomes local to that scope and overrides any variable with the same name in the global or outer scope.

var +=1 is similar to var = var + 1 , therefore the Python interpreter should first read var , perform the addition and assign the value back to var .

var is a variable local to test_func , so the variable is read or referenced before we have assigned it. As a result, the Python interpreter raises the UnboundLocalError.

Example #1: Accessing a Local Variable

Let’s look at an example where we define a global variable number. We will use the increment_func to increase the numerical value of number by 1.

Let’s run the code to see what happens:

The error occurs because we tried to read a local variable before assigning a value to it.

We can solve this error by passing a parameter to increment_func . This solution is the preferred approach. Typically Python developers avoid declaring global variables unless they are necessary. Let’s look at the revised code:

We have assigned a value to number and passed it to the increment_func , which will resolve the UnboundLocalError. Let’s run the code to see the result:

We successfully printed the value to the console.

We also can solve this error by using the global keyword. The global statement tells the Python interpreter that inside increment_func , the variable number is a global variable even if we assign to it in increment_func . Let’s look at the revised code:

Let’s run the code to see the result:

Example #2: Function with if-elif statements

Let’s look at an example where we collect a score from a player of a game to rank their level of expertise. The variable we will use is called score and the calculate_level function takes in score as a parameter and returns a string containing the player’s level .

In the above code, we have a series of if-elif statements for assigning a string to the level variable. Let’s run the code to see what happens:

The error occurs because we input a score equal to 40 . The conditional statements in the function do not account for a value below 55 , therefore when we call the calculate_level function, Python will attempt to return level without any value assigned to it.

We can solve this error by completing the set of conditions with an else statement. The else statement will provide an assignment to level for all scores lower than 55 . Let’s look at the revised code:

In the above code, all scores below 55 are given the beginner level. Let’s run the code to see what happens:

We can also create a global variable level and then use the global keyword inside calculate_level . Using the global keyword will ensure that the variable is available in the local scope of the calculate_level function. Let’s look at the revised code.

In the above code, we put the global statement inside the function and at the beginning. Note that the “default” value of level is beginner and we do not include the else statement in the function. Let’s run the code to see the result:

Congratulations on reading to the end of this tutorial! The UnboundLocalError: local variable referenced before assignment occurs when you try to reference a local variable before assigning a value to it. Preferably, you can solve this error by passing parameters to your function. Alternatively, you can use the global keyword.

If you have if-elif statements in your code where you assign a value to a local variable and do not account for all outcomes, you may encounter this error. In which case, you must include an else statement to account for the missing outcome.

For further reading on Python code blocks and structure, go to the article: How to Solve Python IndentationError: unindent does not match any outer indentation level .

Go to the online courses page on Python to learn more about Python for data science and machine learning.

Have fun and happy researching!

[SOLVED] Local Variable Referenced Before Assignment

Python treats variables referenced only inside a function as global variables. Any variable assigned to a function’s body is assumed to be a local variable unless explicitly declared as global.

Why Does This Error Occur?

Unboundlocalerror: local variable referenced before assignment occurs when a variable is used before its created. Python does not have the concept of variable declarations. Hence it searches for the variable whenever used. When not found, it throws the error.

Before we hop into the solutions, let’s have a look at what is the global and local variables.

Local Variable Declarations vs. Global Variable Declarations

Local Variables	Global Variables
A variable is declared primarily within a Python function.	Global variables are in the global scope, outside a function.
A local variable is created when the function is called and destroyed when the execution is finished.	A Variable is created upon execution and exists in memory till the program stops.
Local Variables can only be accessed within their own function.	All functions of the program can access global variables.
Local variables are immune to changes in the global scope. Thereby being more secure.	Global Variables are less safer from manipulation as they are accessible in the global scope.

[Fixed] typeerror can’t compare datetime.datetime to datetime.date

Local Variable Referenced Before Assignment Error with Explanation

Try these examples yourself using our Online Compiler.

Let’s look at the following function:

Local Variable Referenced Before Assignment Error

Explanation

The variable myVar has been assigned a value twice. Once before the declaration of myFunction and within myFunction itself.

Using Global Variables

Passing the variable as global allows the function to recognize the variable outside the function.

Create Functions that Take in Parameters

Instead of initializing myVar as a global or local variable, it can be passed to the function as a parameter. This removes the need to create a variable in memory.

UnboundLocalError: local variable ‘DISTRO_NAME’

This error may occur when trying to launch the Anaconda Navigator in Linux Systems.

Upon launching Anaconda Navigator, the opening screen freezes and doesn’t proceed to load.

Try and update your Anaconda Navigator with the following command.

If solution one doesn’t work, you have to edit a file located at

After finding and opening the Python file, make the following changes:

In the function on line 159, simply add the line:

DISTRO_NAME = None

Save the file and re-launch Anaconda Navigator.

DJANGO – Local Variable Referenced Before Assignment [Form]

The program takes information from a form filled out by a user. Accordingly, an email is sent using the information.

Upon running you get the following error:

We have created a class myForm that creates instances of Django forms. It extracts the user’s name, email, and message to be sent.

A function GetContact is created to use the information from the Django form and produce an email. It takes one request parameter. Prior to sending the email, the function verifies the validity of the form. Upon True , .get() function is passed to fetch the name, email, and message. Finally, the email sent via the send_mail function

Why does the error occur?

We are initializing form under the if request.method == “POST” condition statement. Using the GET request, our variable form doesn’t get defined.

Local variable Referenced before assignment but it is global

This is a common error that happens when we don’t provide a value to a variable and reference it. This can happen with local variables. Global variables can’t be assigned.

This error message is raised when a variable is referenced before it has been assigned a value within the local scope of a function, even though it is a global variable.

Here’s an example to help illustrate the problem:

In this example, x is a global variable that is defined outside of the function my_func(). However, when we try to print the value of x inside the function, we get a UnboundLocalError with the message “local variable ‘x’ referenced before assignment”.

This is because the += operator implicitly creates a local variable within the function’s scope, which shadows the global variable of the same name. Since we’re trying to access the value of x before it’s been assigned a value within the local scope, the interpreter raises an error.

To fix this, you can use the global keyword to explicitly refer to the global variable within the function’s scope:

However, in the above example, the global keyword tells Python that we want to modify the value of the global variable x, rather than creating a new local variable. This allows us to access and modify the global variable within the function’s scope, without causing any errors.

Local variable ‘version’ referenced before assignment ubuntu-drivers

This error occurs with Ubuntu version drivers. To solve this error, you can re-specify the version information and give a split as 2 –

Here, p_name means package name.

With the help of the threading module, you can avoid using global variables in multi-threading. Make sure you lock and release your threads correctly to avoid the race condition.

When a variable that is created locally is called before assigning, it results in Unbound Local Error in Python. The interpreter can’t track the variable.

Therefore, we have examined the local variable referenced before the assignment Exception in Python. The differences between a local and global variable declaration have been explained, and multiple solutions regarding the issue have been provided.

How to Solve Error - Local Variable Referenced Before Assignment in Python

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How to Solve Error - Local Variable …

Check the Variable Scope to Fix the local variable referenced before assignment Error in Python

Initialize the variable before use to fix the local variable referenced before assignment error in python, use conditional assignment to fix the local variable referenced before assignment error in python.

How to Solve Error - Local Variable Referenced Before Assignment in Python

This article delves into various strategies to resolve the common local variable referenced before assignment error. By exploring methods such as checking variable scope, initializing variables before use, conditional assignments, and more, we aim to equip both novice and seasoned programmers with practical solutions.

Each method is dissected with examples, demonstrating how subtle changes in code can prevent this frequent error, enhancing the robustness and readability of your Python projects.

The local variable referenced before assignment occurs when some variable is referenced before assignment within a function’s body. The error usually occurs when the code is trying to access the global variable.

The primary purpose of managing variable scope is to ensure that variables are accessible where they are needed while maintaining code modularity and preventing unexpected modifications to global variables.

We can declare the variable as global using the global keyword in Python. Once the variable is declared global, the program can access the variable within a function, and no error will occur.

The below example code demonstrates the code scenario where the program will end up with the local variable referenced before assignment error.

In this example, my_var is a global variable. Inside update_var , we attempt to modify it without declaring its scope, leading to the Local Variable Referenced Before Assignment error.

We need to declare the my_var variable as global using the global keyword to resolve this error. The below example code demonstrates how the error can be resolved using the global keyword in the above code scenario.

In the corrected code, we use the global keyword to inform Python that my_var references the global variable.

When we first print my_var , it displays the original value from the global scope.

After assigning a new value to my_var , it updates the global variable, not a local one. This way, we effectively tell Python the scope of our variable, thus avoiding any conflicts between local and global variables with the same name.

python local variable referenced before assignment - output 1

Ensure that the variable is initialized with some value before using it. This can be done by assigning a default value to the variable at the beginning of the function or code block.

The main purpose of initializing variables before use is to ensure that they have a defined state before any operations are performed on them. This practice is not only crucial for avoiding the aforementioned error but also promotes writing clear and predictable code, which is essential in both simple scripts and complex applications.

In this example, the variable total is used in the function calculate_total without prior initialization, leading to the Local Variable Referenced Before Assignment error. The below example code demonstrates how the error can be resolved in the above code scenario.

In our corrected code, we initialize the variable total with 0 before using it in the loop. This ensures that when we start adding item values to total , it already has a defined state (in this case, 0).

This initialization is crucial because it provides a starting point for accumulation within the loop. Without this step, Python does not know the initial state of total , leading to the error.

python local variable referenced before assignment - output 2

Conditional assignment allows variables to be assigned values based on certain conditions or logical expressions. This method is particularly useful when a variable’s value depends on certain prerequisites or states, ensuring that a variable is always initialized before it’s used, thereby avoiding the common error.

In this example, message is only assigned within the if and elif blocks. If neither condition is met (as with guest ), the variable message remains uninitialized, leading to the Local Variable Referenced Before Assignment error when trying to print it.

The below example code demonstrates how the error can be resolved in the above code scenario.

In the revised code, we’ve included an else statement as part of our conditional logic. This guarantees that no matter what value user_type holds, the variable message will be assigned some value before it is used in the print function.

This conditional assignment ensures that the message is always initialized, thereby eliminating the possibility of encountering the Local Variable Referenced Before Assignment error.

python local variable referenced before assignment - output 3

Throughout this article, we have explored multiple approaches to address the Local Variable Referenced Before Assignment error in Python. From the nuances of variable scope to the effectiveness of initializations and conditional assignments, these strategies are instrumental in developing error-free code.

The key takeaway is the importance of understanding variable scope and initialization in Python. By applying these methods appropriately, programmers can not only resolve this specific error but also enhance the overall quality and maintainability of their code, making their programming journey smoother and more rewarding.

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Python: How to Avoid Syntax Errors When Referencing Variables Before Assignment

**Python Variable Referenced Before Assignment: A Common Error**

In Python, variables must be assigned a value before they can be used. This means that you cannot use a variable in an expression before you have assigned it a value. For example, the following code will generate an error:

python >>> x = 1 + 2 >>> print(x)

This error occurs because the variable `x` has not yet been assigned a value. To fix this error, we can assign a value to `x` before using it in an expression:

python >>> x = 1 + 2 >>> print(x) 3

This code will now print the value `3` to the console.

Why Does This Error Occur?

The reason why this error occurs is because Python is a **strongly typed** language. This means that each variable has a specific type, and the type of a variable cannot be changed once it has been assigned. In the example above, the variable `x` is of type `int`. This means that it can only store whole numbers. When we try to add `x` to `2`, Python throws an error because `x` does not have a value yet.

How Can I Avoid This Error?

The easiest way to avoid this error is to make sure that you assign a value to all of your variables before you use them. You can do this by either assigning a value to the variable in the same statement that you declare it, or by assigning a value to the variable in a previous statement.

For example, the following code will not generate an error:

python >>> x = 1 >>> y = 2 >>> z = x + y >>> print(z) 3

In this code, the variable `x` is assigned the value `1` in the first statement. The variable `y` is assigned the value `2` in the second statement. The variable `z` is then assigned the value of `x + y` in the third statement. This code will print the value `3` to the console.

The error `variable referenced before assignment` is a common error in Python. It can be avoided by making sure that you assign a value to all of your variables before you use them.

Python Variable	Error Message	Solution
x	NameError: name ‘x’ is not defined	Assign a value to the variable before using it.
y = x + 1	SyntaxError: invalid syntax	Variables must be assigned values on the same line.
z = x + y	NameError: name ‘x’ is not defined	Assign a value to the variable before using it.

In Python, a variable referenced before assignment is an error that occurs when a variable is used in an expression before it has been assigned a value. This can lead to errors, as the value of the variable is not yet known. There are two main types of variable referenced before assignment errors:

* **Undeclared variables:** A variable is referenced before it has been declared. * **Uninitialized variables:** A variable is referenced before it has been initialized.

In this tutorial, we will discuss what variable referenced before assignment is, why it occurs, and how to fix it. We will also provide some examples of variable referenced before assignment errors.

**What is a variable referenced before assignment?**

A variable referenced before assignment occurs when a variable is used in an expression before it has been assigned a value. This can lead to errors, as the value of the variable is not yet known.

For example, the following code will cause a variable referenced before assignment error:

python >>> x = y >>> print(x)

In this code, the variable `x` is referenced before it has been assigned a value. This will cause an error, as the value of `x` is not yet known.

**Why does variable referenced before assignment occur?**

There are a number of reasons why variable referenced before assignment can occur:

* **Incorrect code:** The programmer may have accidentally referenced a variable before it has been assigned a value. * **Typos:** The programmer may have misspelled a variable name, causing it to be referenced before it has been assigned a value. * **Variable shadowing:** A variable with the same name as another variable is declared in an inner scope, shadowing the outer variable.

**How to fix variable referenced before assignment errors**

There are a few ways to fix variable referenced before assignment errors.

* **Declare the variable before using it:** The simplest way to fix a variable referenced before assignment error is to declare the variable before using it. For example, the following code will fix the error from the previous example:

python >>> x = 0 >>> print(x) 0

* **Initialize the variable before using it:** Another way to fix a variable referenced before assignment error is to initialize the variable before using it. For example, the following code will also fix the error from the previous example:

python >>> x = 1 >>> print(x) 1

* **Use the `global` keyword:** If you need to reference a variable before it has been declared in the current scope, you can use the `global` keyword. The `global` keyword tells Python that the variable is defined in the global scope, and not in the current scope. For example, the following code will fix the error from the previous example:

python >>> global x >>> x = 1 >>> print(x) 1

**Examples of variable referenced before assignment errors**

Here are some examples of variable referenced before assignment errors:

>>> x = y >>> print(x)

>>> x = 1 + y >>> print(x)

def foo(): x = 1 return x

Variable referenced before assignment is an error that can occur in Python when a variable is used in an expression before it has been assigned a value. This can lead to errors, as the value of the variable is not yet known. There are a few ways to fix variable referenced before assignment errors, including declaring the variable before using it, initializing the variable before using it, or using the `global` keyword.

How to fix variable referenced before assignment errors?

Variable referenced before assignment is a common error in Python that can cause your code to not work as expected. This error occurs when you try to use a variable before it has been assigned a value.

There are a number of ways to fix variable referenced before assignment errors. Here are three of the most common methods:

Declare the variable before using it. This is the simplest and most effective way to fix this error. To declare a variable, simply use the `var` keyword followed by the variable name and an equal sign (=). For example:

python my_variable = 10

Initialize the variable before using it. Another way to fix variable referenced before assignment errors is to initialize the variable before using it. To initialize a variable, simply assign it a value. For example:

python my_variable = “Hello world!”

Use a different variable name. If the variable is being shadowed, you can use a different variable name to avoid the conflict. For example, if you have a variable named `my_variable` that is being shadowed by a function parameter, you can use a different variable name, such as `my_new_variable`.

Here is an example of how to fix a variable referenced before assignment error:

python def my_function(my_variable): This will cause an error because my_variable is not declared before it is used. print(my_variable)

To fix this error, we can declare my_variable before calling my_function(). my_variable = “Hello world!”

my_function(my_variable)

Variable referenced before assignment is a common error that can lead to problems in your code. By following the tips in this article, you can avoid this error and ensure that your code is error-free.

Q: What does it mean to reference a Python variable before assignment?

A: When you reference a Python variable before it has been assigned a value, you are getting an error. This is because Python does not know what value to assign to the variable, and it cannot proceed with your code.

Q: Why does this error occur?

A: The error occurs because Python follows the following rules for variable assignment:

1. A variable must be declared before it can be used. 2. A variable must be assigned a value before it can be used.

When you reference a variable before it has been assigned a value, you are violating these rules. This is why you get an error.

Q: How can I avoid this error?

A: There are two ways to avoid this error:

1. You can declare the variable and assign it a value in the same statement. 2. You can declare the variable and then assign it a value later in your code.

Here are some examples:

python Example 1: Declare and assign a variable in the same statement x = 10

Example 2: Declare a variable and assign it a value later y = None y = 20

Q: What are the consequences of referencing a Python variable before assignment?

A: The consequences of referencing a Python variable before assignment can vary depending on the context. In some cases, you may simply get an error. In other cases, your code may run incorrectly.

It is always best to avoid referencing a Python variable before assignment to ensure that your code is correct and runs as expected.

Q: How can I debug a Python error that involves referencing a variable before assignment?

A: If you get an error that involves referencing a Python variable before assignment, you can debug the error by following these steps:

1. Identify the line of code that is causing the error. 2. Check to make sure that the variable has been declared before it is used. 3. Check to make sure that the variable has been assigned a value before it is used. 4. If the variable has been declared and assigned a value, but you are still getting an error, you may need to check the type of the variable. Make sure that the variable is assigned a value that is compatible with its type.

Here is an example of how you can debug a Python error that involves referencing a variable before assignment:

python This code will cause an error because the variable `x` is referenced before it is assigned a value. print(x)

To debug this error, we can use the following steps:

1. Identify the line of code that is causing the error.

In this case, the line of code that is causing the error is `print(x)`.

2. Check to make sure that the variable has been declared before it is used.

In this case, the variable `x` has not been declared before it is used.

3. Check to make sure that the variable has been assigned a value before it is used.

In this case, the variable `x` has not been assigned a value.

4. If the variable has been declared and assigned a value, but you are still getting an error, you may need to check the type of the variable. Make sure that the variable is assigned a value that is compatible with its type.

In this case, the variable `x` is of type `int`, so it must be assigned a value that is an integer.

To fix this error, we can add the following line of code to the program: x = 10

Now, when we run the program, the error will be gone.

In this blog post, we discussed the Python error variable referenced before assignment. We explained what this error means and how to fix it. We also provided some tips for avoiding this error in the future.

Here are the key takeaways from this blog post:

The variable referenced before assignment error occurs when you try to use a variable before it has been assigned a value.
To fix this error, you must assign a value to the variable before you try to use it.
You can avoid this error by being careful not to use variables before they have been assigned a value.
You can also use the `is` operator to check if a variable has been assigned a value before you try to use it.

We hope this blog post has been helpful! If you have any other questions about Python, please feel free to contact us.

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Local variable referenced before assignment in Python

In Python, while working with functions, you can encounter various types of errors. A common error when working with the functions is “ Local variable referenced before assignment ”. The stated error occurs when a local variable is referenced before being assigned any value.

This write-up will provide the possible reasons and the appropriate solutions to the error “Local variable referenced before assignment” with practical examples. The following aspects are discussed in this write-up in detail:

Reason: Reference a Local Variable

Solution 1: mark the variable globally, solution 2: using function parameter value, solution 3: using nonlocal keyword.

The main reason for the “ local variable referenced before assignment ” error in Python is using a variable that does not have local scope. This also means referencing a local variable without assigning it a value in a function.

The variable initialized inside the function will only be accessed inside the function, and these variables are known as local variables. To use variables in the entire program, variables must be initialized globally. The below example illustrates how the “ UnboundLocalError ” occurs in Python.

In the above snippet, the “ Student ” variable is not marked as global, so when it is accessed inside the function, the Python interpreter returns an error.

Note: We can access the outer variable inside the function, but when the new value is assigned to a variable, the “UnboundLocalError” appears on the screen.

To solve this error, we must mark the “ Student ” variable as a global variable using the keyword “ global ” inside the function.

Within the function, we can assign a new value to the student variable without any error. Let’s have a look at the below snippet for a detailed understanding:

In the above code, the local variable is marked as a “ global ” variable inside the function. We can easily reference the variable before assigning the variable in the program.

The above snippet proves that the global keyword resolves the “unboundLocalError”.

Passing a value as an argument to the function will also resolve the stated error. The function accepts the variable as an argument and uses the argument value inside the function. Let’s have a look at the given below code block for a better understanding:

In the above code, the variable is referenced before assigning the value inside the user-defined function. The program executes successfully without any errors because the variable is passed as a parameter value of the function.

The above output shows the value of the function when the function is accessed in the program without any “ Local Variable referenced ” error.

The “ nonlocal ” keyword is utilized in the program to assign a new value to a local variable of function in the nested function. Here is an example of code:

In the above code, the keyword “ nonlocal ” is used to mark the local variable of the outer function as nonlocal. After making the variable nonlocal, we can reference it before assigning a value without any error.

The above output shows the value of the inner function without any “ local variable referenced ” error in a program.

The “ Local variable referenced before assignment ” appears in Python due to assigning a value to a variable that does not have a local scope. To fix this error, the global keyword, return statement, and nonlocal nested function is used in Python script. The global keywords are used with variables to make it able to access inside and outside the function. The return statement is also used to return the variable’s new value back to function and display the result on the screen. This Python guide presented a detailed overview of the reason and solutions for the error “Local variable referenced before assignment” in Python.

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Python 3: UnboundLocalError: local variable referenced before assignment

This error occurs when you are trying to access a variable before it has been assigned a value. Here is an example of a code snippet that would raise this error:

Watch a video course Python - The Practical Guide

The error message will be:

In this example, the variable x is being accessed before it is assigned a value, which is causing the error. To fix this, you can either move the assignment of the variable x before the print statement, or give it an initial value before the print statement.

Both will work without any error.

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></center></p><h2>Local variable referenced before assignment: The UnboundLocalError in Python</h2><p>When you start introducing functions into your code, you’re bound to encounter an UnboundLocalError at some point. Because you try to use a local variable referenced before assignment. So, in this guide, we talk about what this error means and why it is raised. We walk through an example in action to help you understand how you can solve it.</p><p>Source: careerkarma</p><p><center><img style=

What is UnboundLocalError: local variable referenced before assignment?

Trying to assign a value to a variable that does not have local scope can result in this error:

Python has a simple rule to determine the scope of a variable. To clarify, a variable is assigned in a function, that variable is local. Because it is assumed that when you define a variable inside a function, you only need to access it inside that function.

There are two variable scopes in Python: local and global. Global variables are accessible throughout an entire program. Whereas, local variables are only accessible within the function in which they are originally defined.

An example of Local variable referenced before assignment

We’re going to write a program that calculates the grade a student has earned in class.

Firstly, we start by declaring two variables:

These variables store the numerical and letter grades a student has earned, respectively. By default, the value of “letter” is “F”. Then, we write a function that calculates a student’s letter grade based on their numerical grade using an “if” statement:

Finally, we call our function:

Let’s run our code of Local variable referenced before assignment and see what happens:

Here is an error!

The Solution of Local variable referenced before assignment

The code returns an error: Unboundlocalerror local variable referenced before assignment because we reference “letter” before we assign it.

Moreover, we do define “letter” at the start of our program. However, we define it in the global context. Because Python treats “return letter” as trying to return a local variable called “letter”, not a global variable.

Therefore, this problem of variable referenced before assignment could be solved in two ways. Firstly, we can add an else statement to our code. This ensures we declare “letter” before we try to return it:

Let’s try to run our code again:

Our code successfully prints out the student’s grade. This approach is good because it lets us keep “letter” in the local context. To clarify, we could even remove the “letter = “F”” statement from the top of our code because we do not use it in the global context.

Alternatively, we could use the “global” keyword to make our global keyword available in the local context in our calculate_grade() function:

We use the “global” keyword at the start of our function.

This keyword changes the scope of our variable to a global variable. This means the “return” statement will no longer treat “letter” like a local variable. Let’s run our code. Our code returns: F.

The code works successfully! Let’s try it using a different grade number by setting the value of “numerical” to a new number:

Our code returns: B.

Finally, we have fixed the local variable referenced before assignment error in the code.

To sum up, as you can see, the UnboundLocalError: local variable referenced before assignment error is raised when you try to assign a value to a local variable before it has been declared. Then, you can solve this error by ensuring that a local variable is declared before you assign it a value. Moreover, if a variable is declared globally that you want to access in a function, you can use the “global” keyword to change its value. In case you have any inquiry, let’s CONTACT US . With a lot of experience in Mobile app development services , we will surely solve it for you instantly.

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Defining a symbolic syntax for referring to assignment targets

FWIW, aside from the potential performance hit, mutating f_locals should work reliably in 3.13+ due to PEP 667 – Consistent views of namespaces | peps.python.org

I actually had thought about that too but the problem was that we can’t use a soft keyword for it since there is no way syntactically to distinguish the soft keyword from a variable name, and if we make it a hard keyword then it would be too much of a breaking change since the keyword would have to be a commonly used English word that likely collides with variable names in existing code base.

But now it occurred to me that we can just make the magic placeholder a dunder so no existing code base should be using it. As for the name itself, I think __target__ would be good:

The code now looks a lot less cryptic/Perlish to me.

Behind the scene though, __target__ would be a hard keyword rather than a variable name. It won’t be looked up in the namespace but is rather expanded at compilation time.

Similarlly, @'' can be made into a new hard keyword such as __target_name__ to look less cryptic.

Yup, same here. I almost wrote my own POV comparing this to walrus, but decided not to half-way through realising that it isn’t going to be of much use given this is currently at contemplative stage.

And it took me a fair bit of time to stop abusing walrus, however I am happy about it having finally learned to use it responsibly.

The notation, I think is decent - visually and semantically. And been wandering what was the reason for @ for mat_mult - never seen @ used anywhere in math before. There was quite a good example for this - matlab . Can’t do exactly the same, but retaining * might have been better, e.g. \* . So that @ could be used for something more appropriate, e.g. this. But given status quo, I don’t think it would fly. So 2 options:

Change matrix multiplication operator. Been thinking about how hard of a sell this would be. I know that no-one would want to do it. All the backwards compatibility etc, but has anyone analysed compound cost of a bad decision? And the fact that the earlier the correction is done, the smaller the damage? I am talking in general, not only this specific case. I mean surely if the goal is best possible version of Python, (as opposed to pleasing unsatisfied and reluctant to adapt users), big breaks of backwards compatibility are inevitable…
Pick something else for this. One idea would be to go with bash-like argument syntax, but with pythonic slicing:

Or maybe even star, given it being used in expansions:

Could also incorporate string-like formatting:

Alternatively, use * for strings, @ for values (similar to what bash does).

We have space-separated names as arguments in the standard library too, such as collections.namedtuple and enum.Enum :

Using my dunder keyword idea above, it can become:

The matrix multiplication PEP did cover that: PEP 465 – A dedicated infix operator for matrix multiplication | peps.python.org

The __target__ dunder idea is interesting, as it doesn’t provide brevity gains in most cases, but does provide the benefit of avoiding repeated evaluation.

I suspect code that assigns to identifiers would continue to be better off just using the target identifier directly, but attribute access, subscripting, slicing, and tuple assignment could still see some utility.

__target_text__ could replace @'' for both identifier assignment and tuple assignment ( __target_name__ wouldn’t match the latter use case)

I doubt you could reasonably use that form to map function parameters to local variables of the same name, though.

Sounds good indeed. With the name __target_text__ we wouldn’t have to worry about a plural form.

I don’t see why not. We can name the new keyword that forwards local variables to function parameters of the same names, __same__ . The compiler with access to AST can clearly tell which keyword argument a ast.Same node belongs to and produces bytecode that loads the local variable of that name for the argument accordingly:

This is really a completely separate proposal from the assignment target placeholder proposal though, and should be discussed about in a separate thread (perhaps in the PEP-736 thread, in which I have now made a post ).

Yeah the loss of brevity does take away the utility of this idea in cases of a single identifier, particularly as an alternative to PEP-736, where parameter names are always single identifiers.

I agree that we should focus more on its utility for more complex assignment targets.

Going further on the SymPy tangent, I can brainstorm a possible story of how to get that by more straightforward extensions of existing syntax.

The hardest hurdle in this story is the first step. Suppose Python somehow gets dict destructuring assignment:

Sympy then defines a helper whose __getitem__ gives out symbols (if it doesn’t already have it):

By this time PEP 736 has been accepted, and its syntax gets extended to dict destructuring:

(Is that Perlish?) (Is it the direction Python is going?)

People now start writing {Point2D=} = namedtuplemaker('x', 'y') … which isn’t straightforward to read today, but maybe it’s better than with @'' ?

“Whatever, we have to pick something.”

If you’re going to give the target a full identifier, you might as well provide the name rather than hardcoding it

some.nested.attribute as x = x.lower()

This doesn’t require new tokens, and the syntax mimics what we have in the match statement (which tries to overlap assignment syntax). It definitely looks more python than perl (keywords vs symbols)

Same as your proposal, this doesn’t cover argument pushing, but only double evaluation (at this point it isn’t much more than a glorified walrus). This is also missing a syntax to capture the name of the target as a str. I’m not sorry convinced on that but I think you could do (a, b, c) as (_, names) = simpy.symbols(names) .

I’m not super sold into this either, but hopefully putting this idea on the table may help someone find a better proposal

For me a big part of this feature was not needing to assign a name for this specific “some.nested.attribute”, so I’m not really sure I like the as proposal

A benefit can be that if the name persists, it can be used more times in the code that follows the assignment.

Quite like it, one issue though:

While naming tuple thing obstruct such intuitive expansion. However might not be an issue as one can always slice it on the right hand side. However, it does not seem very elegant nevertheless. Maybe something like:

This would be the 2nd method that allows extracting identifier name from identifier. First one being f{a=} . However, it would also be the second one which compulsory does more than that, while simple straight forward way to do this still does not exist, namely something similar to C# nameof , that would do exactly that without needing to evaluate anything. Thinking if I could hack this for it:

Interesting idea, for sure.

What I don’t like about it is that it encourages a coding style that binds multiple different values to the same name. Inevitably, one of those values is going to be badly named.

E.g. you might see

At point (1) , the value of sth.this_must_be_lowercase violates requirements: The value is in fact not guaranteed lowercase.

I would rather it was written such that different values have different names. Like this:

This is a fairly marginal coding style distinction, and not something I would usually make a fuss about. But I do think the latter style is marginally better, and it would be unfortunate to add syntax that encourages the former style.

I am -1 to using @ for any of the purposes outlined here, but +1 to long_name as x = foo(x) being sugar for long_name = foo('long_name') .

It should work the same for dotted names and tuples, i.e. a.b. c as x = foo(x) would be sugar for a.b. c = foo('a.b.c') and (a,*b, c) as x = foo(x) would be sugar for (a,*b, c) = foo('a, *b, c') - note my intentional inconsistent whitespace to demonstrate that whitespace ought to be normalised when generating the string representation.

Outer parens in tuple assignment would be required to make it clearly unambiguous; a, b as x would be a syntax error but might later (as a separate proposal) be allowed in order to let x be 'b' . I’m -0 on allowing this from the beginning; probably better to see how the general idea works out before adding in this complication.

I would prefer that this feature be limited to passing the string representation of some name to a function (or otherwise using it in an expression), as that’s an actually important use case (namedtuple, TypeVar). My dislike of using this for accessing the target object itself is pretty much what @AndersMunch has already explained: it’s far less confusing to just use a regular ol’ assignment for that.

“Python is not Perl” indeed!

IMO another good (also English-specific) mnemonic is “at rhymes with that”, and reading @ as “that” is a pretty natural way to speak the statement.

I suspect that I’m in the minority here but I personally found figuring out what assignment target means (i.e. whatever’s on the the left of the = operator) to be more confusing than mapping a punctuation character to the words assignment target . So perlish or not, to me eliminating @ isn’t really fixing anything.

TBH, in this version of the proposal you don’t get much for TypeVar . You are changing:

if you make up a name and copy it over you’re getting more verbosity than the original and still have repetition. Same for namedtuples. That’s whay I didn’t worry too much about the string representation when I covered this, I was more focused on Alyssa’s idea of avoiding re-evaluation of attribute accesses/slicing.

We have __set_name__ so descriptors know their own name. Have we thought of extending __set_name__ to work on objects? Or perhaps there is a reason why it’s not done? I think it would be neat if objects could capture the lhs as a name like in descriptors

Allowing __target__ on the LFS would make the syntax ambiguous when there is also __target__ on the RHS:

Does __target__[:2] on the RHS become foo[:2] or foo[2:][:2] ?

Assignment to a name does not modify an object in-place. It merely sets the name on the LHS to a new reference to the object on the RHS. So __target__ = hex(v) would just set the local name v to a new object for that iteration rather than updating the entry in mydict , which will still hold a reference to the original value.

Alyssa’s elaborate description of how to deal with different assignment targets may seem confusing, but at its heart it’s something quite simple and familiar: It’s how augmented assignment works.

Just like a.b[c].d += 1 only evaluates a.b[c] once, a.b[c].d = @ + 1 would also evaluate a.b[c] just once.

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Python: local variable 'string' referenced before assignment

I was wondering why i was getting this error for adding a letter to this string from a function. local variable 'string' referenced before assignment

1 update_variables is not defined anywhere. update_string should probably take an input variable or use global (bad idea) – inspectorG4dget Commented Nov 14, 2012 at 6:06
sorry i was editing the code to post on here – Brandon Nadeau Commented Nov 14, 2012 at 6:08

3 Answers 3

You are accessing global variable, need to declare it:

2 it's better if this is done with input params to update_string . global is usually not the best option – inspectorG4dget Commented Nov 14, 2012 at 6:08

There is nowhere for the old 'string' to come from in the local scope of your function, so python assumes you're talking about the one from the outer scope.

Moreover, since strings are immutable the usual pattern is to create a new one and return it, so you might prefer to update your function interface to something more like:

And then you would use it instead like:

You can access the variable from the outer scope inside the function, but you can't assign to it. So the following is a workaround without using global variables or inputs to the function:

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python
I think you are using 'global' incorrectly. See Python reference.You should declare variable without global and then inside the function when you want to access global variable you declare it global yourvar. #!/usr/bin/python total def checkTotal(): global total total = 0
Fix "local variable referenced before assignment" in Python
Learn how to fix this common error in Python when a local variable is used before it is assigned a value. See examples, explanations, and solutions involving initialization, global keyword, and variable scope.
How to Fix
Output. Hangup (SIGHUP) Traceback (most recent call last): File "Solution.py", line 7, in <module> example_function() File "Solution.py", line 4, in example_function x += 1 # Trying to modify global variable 'x' without declaring it as global UnboundLocalError: local variable 'x' referenced before assignment Solution for Local variable Referenced Before Assignment in Python
How to Fix Local Variable Referenced Before Assignment Error in Python
value = value + 1 print (value) increment() If you run this code, you'll get. BASH. UnboundLocalError: local variable 'value' referenced before assignment. The issue is that in this line: PYTHON. value = value + 1. We are defining a local variable called value and then trying to use it before it has been assigned a value, instead of using the ...
Python local variable referenced before assignment Solution
Learn how to fix the UnboundLocalError: local variable referenced before assignment error in Python. See an example of this error and how to avoid it by using an else statement or the global keyword.
Local variable referenced before assignment in Python
Learn how to fix the error when a local variable is used before being assigned a value in a function. See examples of using global, nonlocal, and return keywords, and how to avoid shadowing global variables.
How to fix UnboundLocalError: local variable 'x' referenced before
Learn why this error occurs when you reference a variable inside a function without assigning it a value, and how to resolve it with different variable names or parameters. See an example code and the best solution to avoid confusion.
Local variable referenced before assignment in Python
Using nonlocal keyword. The nonlocal keyword is used to work with variables inside nested functions, where the variable should not belong to the inner function. It allows you to modify the value of a non-local variable in the outer scope. For example, if you have a function outer that defines a variable x, and another function inner inside outer that tries to change the value of x, you need to ...
4 Ways to Fix Local Variable Referenced Before Assignment Error in Python
Strategy 2: Using the Global Keyword. In Python, variables declared inside a function are considered local variables. Thus, they are separate from other variables declared outside of the function.
UnboundLocalError Local variable Referenced Before Assignment in Python
We use Python assignment statements to assign objects to names. The target of an assignment statement is written on the left side of the equal sign (=), and the object on the right can be an arbitrary expression that computes an object. There are some important properties of assignment in Python :- Assignment creates object references instead of co
Python UnboundLocalError: local variable referenced before assignment
UnboundLocalError: local variable referenced before assignment. Example #1: Accessing a Local Variable. Solution #1: Passing Parameters to the Function. Solution #2: Use Global Keyword. Example #2: Function with if-elif statements. Solution #1: Include else statement. Solution #2: Use global keyword. Summary.
[SOLVED] Local Variable Referenced Before Assignment
Python treats variables referenced only inside a function as global variables. Any variable assigned to a function's body is assumed to be a local variable unless explicitly declared as global. ... Therefore, we have examined the local variable referenced before the assignment Exception in Python. The differences between a local and global ...
Local Variable Referenced Before Assignment in Python
This tutorial explains the reason and solution of the python error local variable referenced before assignment
Referenced before assignment Python
That just defines a function that will, when run, call whatever bar means. As long as we've defined bar before we call it—and we have—everything is fine. However, you have a number of similar problems in your code. For example, let's look at this part: elif aon == 2: def first_number(): print "First number: ".
Python: How to Avoid Syntax Errors When Referencing Variables Before
**What is a variable referenced before assignment?** A variable referenced before assignment occurs when a variable is used in an expression before it has been assigned a value. This can lead to errors, as the value of the variable is not yet known. For example, the following code will cause a variable referenced before assignment error: python
Local variable referenced before assignment in Python
The "Local variable referenced before assignment" appears in Python due to assigning a value to a variable that does not have a local scope. To fix this error, the global keyword, return statement, and nonlocal nested function is used in Python script.
Python 3: UnboundLocalError: local variable referenced before assignment
To fix this, you can either move the assignment of the variable x before the print statement, or give it an initial value before the print statement. def example (): x = 5 print (x) example()
Local variable referenced before assignment: The UnboundLocalError
1 UnboundLocalError: local variable referenced before assignment. Python has a simple rule to determine the scope of a variable. To clarify, a variable is assigned in a function, that variable is local. Because it is assumed that when you define a variable inside a function, you only need to access it inside that function. ...
Python 3: "Local Variable referenced before assignment"
1. You need to declare a global in the function. Python determines name scope per scope. If you assign to a name in a function (or use it as an import target, or a for target, or an argument, etc.) then Python makes that name a local unless stated otherwise. As such, using global at the global level is rather pointless, because Python already ...
Defining a symbolic syntax for referring to assignment targets
Assignment to a name does not modify an object in-place. It merely sets the name on the LHS to a new reference to the object on the RHS. So __target__ = hex(v) would just set the local name v to a new object for that iteration rather than updating the entry in mydict, which will still hold a reference to the original value.
python : local variable is referenced before assignment
6. When Python sees that you are assigning to x it forces it to be a local variable name. Now it becomes impossible to see the global x in that function (unless you use the global keyword) So. Case 1) Since there is no local x, you get the global. Case 2) You are assigning to a local x so all references to x in the function will be the local one.
Python: local variable 'string' referenced before assignment
1. There is nowhere for the old 'string' to come from in the local scope of your function, so python assumes you're talking about the one from the outer scope. Moreover, since strings are immutable the usual pattern is to create a new one and return it, so you might prefer to update your function interface to something more like: return str_in ...

Fix "local variable referenced before assignment" in Python

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The "local variable referenced before assignment" Error

Fixing the Error: Initialization

Fixing the Error: Global Keyword

Similar Error: NameError

Variable Scope in Python

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Local variable referenced before assignment in Python

# Local variable referenced before assignment in Python

# Mark the variable as global to solve the error

# Local variables shadow global ones with the same name

# Returning a value from the function instead

# Passing the global variable as an argument to the function

# Assigning a value to a local variable from an outer scope

# Discussion

# Additional Resources

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Local variable referenced before assignment in Python

Using the global keyword

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Strategy 1: Assigning a Value before Referencing

Strategy 2: Using the Global Keyword

For example:

Strategy 3: Adding Input Parameters for Functions

Strategy 4: Initializing Variables before Loops or Conditionals

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