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Assignment operators.
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Assignment operators modify the value of the object.
Operator name | Syntax | Prototype examples (for class T) | ||
---|---|---|---|---|
Inside class definition | Outside class definition | |||
simple assignment | Yes | T& T::operator =(const T2& b); | ||
addition assignment | Yes | T& T::operator +=(const T2& b); | T& operator +=(T& a, const T2& b); | |
subtraction assignment | Yes | T& T::operator -=(const T2& b); | T& operator -=(T& a, const T2& b); | |
multiplication assignment | Yes | T& T::operator *=(const T2& b); | T& operator *=(T& a, const T2& b); | |
division assignment | Yes | T& T::operator /=(const T2& b); | T& operator /=(T& a, const T2& b); | |
remainder assignment | Yes | T& T::operator %=(const T2& b); | T& operator %=(T& a, const T2& b); | |
bitwise AND assignment | Yes | T& T::operator &=(const T2& b); | T& operator &=(T& a, const T2& b); | |
bitwise OR assignment | Yes | T& T::operator |=(const T2& b); | T& operator |=(T& a, const T2& b); | |
bitwise XOR assignment | Yes | T& T::operator ^=(const T2& b); | T& operator ^=(T& a, const T2& b); | |
bitwise left shift assignment | Yes | T& T::operator <<=(const T2& b); | T& operator <<=(T& a, const T2& b); | |
bitwise right shift assignment | Yes | T& T::operator >>=(const T2& b); | T& operator >>=(T& a, const T2& b); | |
this, and most also return *this so that the user-defined operators can be used in the same manner as the built-ins. However, in a user-defined operator overload, any type can be used as return type (including void). can be any type including . |
Definitions Assignment operator syntax Built-in simple assignment operator Assignment from an expression Assignment from a non-expression initializer clause Built-in compound assignment operator Example Defect reports See also |
Copy assignment replaces the contents of the object a with a copy of the contents of b ( b is not modified). For class types, this is performed in a special member function, described in copy assignment operator .
replaces the contents of the object a with the contents of b, avoiding copying if possible (b may be modified). For class types, this is performed in a special member function, described in . | (since C++11) |
For non-class types, copy and move assignment are indistinguishable and are referred to as direct assignment .
Compound assignment replace the contents of the object a with the result of a binary operation between the previous value of a and the value of b .
The assignment expressions have the form
target-expr new-value | (1) | ||||||||
target-expr op new-value | (2) | ||||||||
target-expr | - | the expression to be assigned to |
op | - | one of *=, /= %=, += -=, <<=, >>=, &=, ^=, |= |
new-value | - | the expression (until C++11) (since C++11) to assign to the target |
If new-value is not an expression, the assignment expression will never match an overloaded compound assignment operator. | (since C++11) |
For the built-in simple assignment, the object referred to by target-expr is modified by replacing its value with the result of new-value . target-expr must be a modifiable lvalue.
The result of a built-in simple assignment is an lvalue of the type of target-expr , referring to target-expr . If target-expr is a bit-field , the result is also a bit-field.
If new-value is an expression, it is implicitly converted to the cv-unqualified type of target-expr . When target-expr is a bit-field that cannot represent the value of the expression, the resulting value of the bit-field is implementation-defined.
If target-expr and new-value identify overlapping objects, the behavior is undefined (unless the overlap is exact and the type is the same).
If the type of target-expr is volatile-qualified, the assignment is deprecated, unless the (possibly parenthesized) assignment expression is a or an . | (since C++20) |
new-value is only allowed not to be an expression in following situations: is of a , and new-value is empty or has only one element. In this case, given an invented variable t declared and initialized as T t = new-value , the meaning of x = new-value is x = t. is of class type. In this case, new-value is passed as the argument to the assignment operator function selected by . <double> z; z = {1, 2}; // meaning z.operator=({1, 2}) z += {1, 2}; // meaning z.operator+=({1, 2}) int a, b; a = b = {1}; // meaning a = b = 1; a = {1} = b; // syntax error | (since C++11) |
In overload resolution against user-defined operators , for every type T , the following function signatures participate in overload resolution:
& operator=(T*&, T*); | ||
volatile & operator=(T*volatile &, T*); | ||
For every enumeration or pointer to member type T , optionally volatile-qualified, the following function signature participates in overload resolution:
operator=(T&, T); | ||
For every pair A1 and A2 , where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signature participates in overload resolution:
operator=(A1&, A2); | ||
The behavior of every built-in compound-assignment expression target-expr op = new-value is exactly the same as the behavior of the expression target-expr = target-expr op new-value , except that target-expr is evaluated only once.
The requirements on target-expr and new-value of built-in simple assignment operators also apply. Furthermore:
In overload resolution against user-defined operators , for every pair A1 and A2 , where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signatures participate in overload resolution:
operator*=(A1&, A2); | ||
operator/=(A1&, A2); | ||
operator+=(A1&, A2); | ||
operator-=(A1&, A2); | ||
For every pair I1 and I2 , where I1 is an integral type (optionally volatile-qualified) and I2 is a promoted integral type, the following function signatures participate in overload resolution:
operator%=(I1&, I2); | ||
operator<<=(I1&, I2); | ||
operator>>=(I1&, I2); | ||
operator&=(I1&, I2); | ||
operator^=(I1&, I2); | ||
operator|=(I1&, I2); | ||
For every optionally cv-qualified object type T , the following function signatures participate in overload resolution:
& operator+=(T*&, ); | ||
& operator-=(T*&, ); | ||
volatile & operator+=(T*volatile &, ); | ||
volatile & operator-=(T*volatile &, ); | ||
Possible output:
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
C++11 | for assignments to class type objects, the right operand could be an initializer list only when the assignment is defined by a user-defined assignment operator | removed user-defined assignment constraint | |
C++11 | E1 = {E2} was equivalent to E1 = T(E2) ( is the type of ), this introduced a C-style cast | it is equivalent to E1 = T{E2} | |
C++20 | compound assignment operators for volatile -qualified types were inconsistently deprecated | none of them is deprecated | |
C++11 | an assignment from a non-expression initializer clause to a scalar value would perform direct-list-initialization | performs copy-list- initialization instead | |
C++20 | bitwise compound assignment operators for volatile types were deprecated while being useful for some platforms | they are not deprecated |
Operator precedence
Operator overloading
Common operators | ||||||
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a = b | ++a | +a | !a | a == b | a[...] | function call |
a(...) | ||||||
comma | ||||||
a, b | ||||||
conditional | ||||||
a ? b : c | ||||||
Special operators | ||||||
converts one type to another related type |
for Assignment operators |
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Im trying to use a variant to be able to store and access two different classes, Node and Nbody, for a barnes Hutt algorithm. However, I get the error:
error: object of type 'std::variant<Nbody, Blank, std::unique_ptr>' cannot be assigned because its copy assignment operator is implicitly deleted
Here is the header file sections using that.. If more code is nessecary I can provide:
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In C++, the assignment operator forms the backbone of many algorithms and computational processes by performing a simple operation like assigning a value to a variable. It is denoted by equal sign ( = ) and provides one of the most basic operations in any programming language that is used to assign some value to the variables in C++ or in other words, it is used to store some kind of information.
The right-hand side value will be assigned to the variable on the left-hand side. The variable and the value should be of the same data type.
The value can be a literal or another variable of the same data type.
In C++, the assignment operator can be combined into a single operator with some other operators to perform a combination of two operations in one single statement. These operators are called Compound Assignment Operators. There are 10 compound assignment operators in C++:
Lets see each of them in detail.
In C++, the addition assignment operator (+=) combines the addition operation with the variable assignment allowing you to increment the value of variable by a specified expression in a concise and efficient way.
This above expression is equivalent to the expression:
The subtraction assignment operator (-=) in C++ enables you to update the value of the variable by subtracting another value from it. This operator is especially useful when you need to perform subtraction and store the result back in the same variable.
In C++, the multiplication assignment operator (*=) is used to update the value of the variable by multiplying it with another value.
The division assignment operator divides the variable on the left by the value on the right and assigns the result to the variable on the left.
The modulus assignment operator calculates the remainder when the variable on the left is divided by the value or variable on the right and assigns the result to the variable on the left.
This operator performs a bitwise AND between the variable on the left and the value on the right and assigns the result to the variable on the left.
The bitwise OR assignment operator performs a bitwise OR between the variable on the left and the value or variable on the right and assigns the result to the variable on the left.
The bitwise XOR assignment operator performs a bitwise XOR between the variable on the left and the value or variable on the right and assigns the result to the variable on the left.
The left shift assignment operator shifts the bits of the variable on the left to left by the number of positions specified on the right and assigns the result to the variable on the left.
The right shift assignment operator shifts the bits of the variable on the left to the right by a number of positions specified on the right and assigns the result to the variable on the left.
Also, it is important to note that all of the above operators can be overloaded for custom operations with user-defined data types to perform the operations we want.
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Assignment operators are used in programming to assign values to variables. We use an assignment operator to store and update data within a program. They enable programmers to store data in variables and manipulate that data. The most common assignment operator is the equals sign (=), which assigns the value on the right side of the operator to ...
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Assignment Operators in C are used to assign values to the variables. The left side operand is called a variable and the right side operand is the value. The value on the right side of the "=" is assigned to the variable on the left side of "=". In this C tutorial, we'll understand the types of C programming assignment operators with examples.
Here is a list of the assignment operators that you can find in the C language: Simple assignment operator (=): This is the basic assignment operator, which assigns the value on the right-hand side to the variable on the left-hand side. Example: int x = 10; // Assigns the value 10 to the variable "x". Addition assignment operator (+=): This ...
Comparison operators are used to compare two values (or variables). This is important in programming, because it helps us to find answers and make decisions. The return value of a comparison is either 1 or 0, which means true (1) or false (0). These values are known as Boolean values, and you will learn more about them in the Booleans and If ...
A. The /= operator is a compound assignment operator in C++. It divides the left operand by the right operand and assigns the result to the left operand. It is equivalent to using the / operator and then the = operator separately. Q. What is the most basic operator among all the assignment operators available in the C language? A.
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Correct behavior. CWG 1527. C++11. for assignments to class type objects, the right operand could be an initializer list only when the assignment is defined by a user-defined assignment operator. removed user-defined assignment constraint. CWG 1538. C++11. E1 ={E2} was equivalent to E1 = T(E2) (T is the type of E1), this introduced a C-style cast.
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error: object of type 'std::variant<Nbody, Blank, std::unique_ptr>' cannot be assigned because its copy assignment operator is implicitly deleted. Here is the header file sections using that.. If more code is nessecary I can provide: class Node { public: Area area; int depth; using NodeContent = std::variant<Nbody, Blank, std::unique_ptr<Node ...
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